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解:(3/10)3a = 102 => (3/10)3a+2 = 102×(3/10)2 => (3/10)3a+2 = 32
32b = 103 => 32b-3 = (10/3)3
((3/10)3a+2)2b-3 = (3/10)(3a+2)(2b-3)
(32)2b-3 = (32b-3)2 = ((10/3)3)2 = (10/3)6 = (3/10)-6
(3a + 2)(2b - 3) = -6
解:153x = 35,153 = 35/x
17y = 33,17 = 33/y
35/x-3/y = 153/17 = 9 = 32
5/x-3/y = 2